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1. consider the above illustration of the electromagnetic spectrum. lab…

Question

  1. consider the above illustration of the electromagnetic spectrum. label one side with \longer λ\ and the other side with \shorter λ\.
  2. next label one side with \higher v\ and the other \lower v\.
  3. label one side with \higher energy\ and the other with \lower energy\.
  4. draw arrows between each of the label sets to show the direction in which the trend increases.
  5. which two arrows point the same direction? would this represent a direct or inverse relationship?
  6. which arrows point in opposite directions? would this represent a direct or inverse relationship?
  7. the electromagnetic spectrum includes all forms of radiant energy. radiant or light energy have wavelike behavior, which is why they are considered electromagnetic waves. from longest to shortest wavelength, electromagnetic waves can be ranked as follows: radio waves, microwaves, infrared waves, visible light, ultraviolet rays, x - rays, and gamma rays. label these on the model above.

part 2: use the model below to answer question 8.

  1. in the center of the electromagnetic spectrum, is a category of radiation classified as \visible light\ because it is the only type of electromagnetic radiation that we can see with the human eye. the spectrum of visible light follows the order we see in a rainbow - roy g biv - or red, orange, yellow, green, blue, indigo, violet. use coloring utensils to color in the rectangle above with the colors of visible light, in the correct order.

Explanation:

Step1: Recall wave - property relationships

The speed of light $c$ is related to wavelength $\lambda$ and frequency $
u$ by $c = \lambda
u$. Energy $E$ of a photon is related to frequency by $E=h
u$ (where $h$ is Planck's constant).

Step2: Label wavelength

The side with more spread - out waves has a longer $\lambda$, and the more compressed side has a shorter $\lambda$.

Step3: Label frequency

Since $c = \lambda
u$, when $\lambda$ is shorter, $
u$ is higher. So the side with shorter $\lambda$ has higher $
u$, and the side with longer $\lambda$ has lower $
u$.

Step4: Label energy

Since $E = h
u$, higher $
u$ corresponds to higher energy. So the side with higher $
u$ has higher energy, and the side with lower $
u$ has lower energy.

Step5: Determine arrow directions

The arrows for higher $
u$ and higher energy point in the same direction. This is a direct relationship because as $
u$ increases, $E$ increases ($E = h
u$).

Step6: Determine opposite - direction arrows

The arrows for longer $\lambda$ and higher $
u$ point in opposite directions. This is an inverse relationship because of $c=\lambda
u$.

Step7: Label electromagnetic waves

From left (longer $\lambda$) to right (shorter $\lambda$) on the spectrum, label: radio waves, microwaves, infrared waves, visible light, ultraviolet rays, X - rays, gamma rays.

Step8: Color visible light

Color the rectangle from left to right: red, orange, yellow, green, blue, indigo, violet.

Answer:

  1. Longer $\lambda$ on the more spread - out side, shorter $\lambda$ on the more compressed side.
  2. Higher $

u$ on the shorter $\lambda$ side, lower $
u$ on the longer $\lambda$ side.

  1. Higher energy on the higher $

u$ side, lower energy on the lower $
u$ side.

  1. Arrows from lower to higher for each pair (lower $\lambda$ to higher $\lambda$, lower $

u$ to higher $
u$, lower energy to higher energy).

  1. Arrows for higher $

u$ and higher energy point in the same direction; direct relationship.

  1. Arrows for longer $\lambda$ and higher $

u$ point in opposite directions; inverse relationship.

  1. From left to right: radio waves, microwaves, infrared waves, visible light, ultraviolet rays, X - rays, gamma rays.
  2. Color from left to right: red, orange, yellow, green, blue, indigo, violet.