the conservation of matter can be demonstrated by using chemical equations. which chemical equation demonstrates the conservation of matter?
o i₂ + 5cl₂ + 6h₂o → 2hio₃ + 10hcl
o 2sn + 4hno₃ → sno₂ + 4no₂ + h₂o
o 4p + 5hno₃ → 5no + 3h₃po₄
o cl + 4na → 4nacl

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Accepted Answer

# Explanation:
## Step1: Count atoms in first equation
- **Left - hand side (LHS):**
    - $I$: $2$ atoms ($I_2$)
    - $Cl$: $5\times2 = 10$ atoms ($5Cl_2$)
    - $H$: $6\times2=12$ atoms ($6H_2O$)
    - $O$: $6$ atoms ($6H_2O$)
 - **Right - hand side (RHS):**
    - $I$: $2$ atoms ($2HIO_3$)
    - $Cl$: $10$ atoms ($10HCl$)
    - $H$: $2 + 10=12$ atoms ($2HIO_3+10HCl$)
    - $O$: $2\times3 = 6$ atoms ($2HIO_3$)
## Step2: Count atoms in second equation
 - **LHS:**
    - $Sn$: $2$ atoms ($2Sn$)
    - $H$: $4$ atoms ($4HNO_3$)
    - $N$: $4$ atoms ($4HNO_3$)
    - $O$: $4\times3=12$ atoms ($4HNO_3$)
 - **RHS:**
    - $Sn$: $1$ atom ($SnO_2$)
    - $H$: $2$ atoms ($H_2O$)
    - $N$: $4$ atoms ($4NO_2$)
    - $O$: $2+(4\times2)+1=11$ atoms ($SnO_2 + 4NO_2+H_2O$)
## Step3: Count atoms in third equation
 - **LHS:**
    - $P$: $4$ atoms ($4P$)
    - $H$: $5$ atoms ($5HNO_3$)
    - $N$: $5$ atoms ($5HNO_3$)
    - $O$: $5\times3 = 15$ atoms ($5HNO_3$)
 - **RHS:**
    - $P$: $3$ atoms ($3H_3PO_4$)
    - $H$: $3\times3=9$ atoms ($3H_3PO_4$)
    - $N$: $5$ atoms ($5NO$)
    - $O$: $5+(3\times4)=17$ atoms ($5NO + 3H_3PO_4$)
## Step4: Count atoms in fourth equation
 - **LHS:**
    - $Cl$: $2$ atoms ($Cl_2$)
    - $Na$: $4$ atoms ($4Na$)
 - **RHS:**
    - $Cl$: $4$ atoms ($4NaCl$)
    - $Na$: $4$ atoms ($4NaCl$)

# Answer:
$I_2 + 5Cl_2+6H_2O
ightarrow2HIO_3 + 10HCl$

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QUESTION IMAGE

Question

Explanation:

Step1: Count atoms in first equation

Step2: Count atoms in second equation

Step3: Count atoms in third equation

Step4: Count atoms in fourth equation

Answer: