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conservation in chemical reactions quick check in which chemical equati…

Question

conservation in chemical reactions quick check
in which chemical equation is the number of atoms in the reactants the same as the number of atoms in the products? (1 point)
○ zn + 2hcl → h₂ + zncl₂
○ li₂co₃ → lio + co₂
○ ch₄ + o₂ → co₂ + 2h₂o
○ co₂ + h₂o → ch₂oh + o₂

Explanation:

Step1: Check the first equation

For \(Zn + 2HCl \to H_2+ZnCl_2\),

  • Reactants: \(1\) \(Zn\) atom, \(2\) \(H\) atoms (\(2\times1\) from \(HCl\)), \(2\) \(Cl\) atoms (\(2\times1\) from \(HCl\)).
  • Products: \(2\) \(H\) atoms (\(H_2\)), \(1\) \(Zn\) atom (\(ZnCl_2\)), \(2\) \(Cl\) atoms (\(ZnCl_2\)).

Step2: Check the second equation

For \(Li_2CO_3\to LiO + CO_2\),

  • Reactants: \(2\) \(Li\) atoms (\(Li_2CO_3\)), \(1\) \(C\) atom (\(Li_2CO_3\)), \(3\) \(O\) atoms (\(Li_2CO_3\)).
  • Products: \(1\) \(Li\) atom (\(LiO\)), \(1\) \(C\) atom (\(CO_2\)), \(3\) \(O\) atoms (\(1\) from \(LiO\) and \(2\) from \(CO_2\)). But \(Li\) atoms are not balanced (\(2\) vs \(1\)).

Step3: Check the third equation

For \(CH_4+O_2\to CO_2 + 2H_2O\),

  • Reactants: \(1\) \(C\) atom (\(CH_4\)), \(4\) \(H\) atoms (\(CH_4\)), \(2\) \(O\) atoms (\(O_2\)).
  • Products: \(1\) \(C\) atom (\(CO_2\)), \(4\) \(H\) atoms (\(2\times2\) from \(2H_2O\)), \(4\) \(O\) atoms (\(2\) from \(CO_2\) and \(2\) from \(2H_2O\)). But \(O\) atoms are not balanced (\(2\) vs \(4\)).

Step4: Check the fourth equation

For \(CO_2+H_2O\to CH_2OH+O_2\),

  • Reactants: \(1\) \(C\) atom (\(CO_2\)), \(2\) \(H\) atoms (\(H_2O\)), \(3\) \(O\) atoms (\(2\) from \(CO_2\) and \(1\) from \(H_2O\)).
  • Products: \(1\) \(C\) atom (\(CH_2OH\)), \(3\) \(H\) atoms (\(CH_2OH\)), \(3\) \(O\) atoms (\(1\) from \(CH_2OH\) and \(2\) from \(O_2\)). \(H\) atoms are not balanced (\(2\) vs \(3\)).

Answer:

\(Zn + 2HCl \to H_2 + ZnCl_2\)