QUESTION IMAGE
Question
completing a proof
given: △stu with \\(\overline{st} \parallel \overline{xy}\\)
prove: \\(\frac{sx}{xu} = \frac{ty}{yu}\\)
complete the steps of the proof.
| statements | reasons |
|---|---|
| 2. ∠1 and ∠2 are corresponding angles | 2. def. of corresponding angles |
| 3. ∠3 and ∠4 are corresponding angles | 3. def. of corresponding angles |
| 4. ∠1 ≅ ∠2; ∠3 ≅ ∠4 | 4. corresponding angles theorem |
| 5. ⋆ | 5. aa similarity theorem |
| 6. \\(\frac{su}{xu} = \frac{tu}{yu}\\) | 6. def. of similar triangles |
| 7. \\(su = sx + xu\\); \\(tu = ty + yu\\) | 7. segment addition postulate |
| 8. \\(\frac{sx + xu}{xu} = \frac{ty + yu}{yu}\\) | 8. substitution property |
| 9. \\(\frac{sx}{xu} + \frac{xu}{xu} = \frac{ty}{yu} + \frac{yu}{yu}\\) | 9. addition of fractions |
| 10. \\(\frac{sx}{xu} + 1 = \frac{ty}{yu} + 1\\) | 10. simplification |
| 11. \\(\frac{sx}{xu} = \frac{ty}{yu}\\) | 11. ⋆ |
options for step 5: angle stu is congruent to angle xyu; triangle stu is congruent to triangle xyu; triangle stu is similar to triangle xyu
Step1: Recall AA Similarity
AA (Angle - Angle) similarity theorem states that if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar. We know from steps 2 - 4 that $\angle1\cong\angle2$ and $\angle3\cong\angle4$. So, in $\triangle STU$ and $\triangle XYU$, we have two pairs of congruent angles.
Step2: Apply AA Similarity
For $\triangle STU$ and $\triangle XYU$, $\angle1\cong\angle2$ (corresponding angles) and $\angle3\cong\angle4$ (corresponding angles). By the AA similarity theorem, $\triangle STU\sim\triangle XYU$. So the statement for step 5 should be "triangle STU is similar to triangle XYU".
Step11: Recall Proportionality from Similar Triangles
From step 6, we have $\frac{SU}{XU}=\frac{TU}{YU}$. From step 7, $SU = SX+XU$ and $TU=TY + YU$. After substitution (step 8), addition of fractions (step 9), and simplification (step 10), we get $\frac{SX}{XU}+ 1=\frac{TY}{YU}+1$. Subtracting 1 from both sides (subtraction property of equality), we get $\frac{SX}{XU}=\frac{TY}{YU}$. So the reason for step 11 is "subtraction property of equality" (or equivalent, like "subtracting 1 from both sides"). But for step 5, the correct statement is about the similarity of the triangles.
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For step 5: triangle STU is similar to triangle XYU
For step 11: subtraction property of equality (or equivalent, e.g., "subtract 1 from both sides")