Question

complete the table below. an example of how to fill out the table is in the first row. for the configuration answers, you can not put superscripts (exponents) and thats ok.

element	atomic orbital location (s,p,d,f)	row of element	column of element in orbital location	last electron configuration of element (use the boxes from before)
phosphorous	typ	type	type yc	type
tin	typ	type	type yc	type
copper	typ	type	type yc	type
technetium	typ	type	type yc	type
strontium	typ	type	type yc	type
neon	typ	type	type yc	type
barium	typ	type	type yc	type
iodine	typ	type	type yc	type

Explanation:

Step1: Identify electron - orbital locations

Phosphorus (P) has an atomic number of 15. Its electron - configuration is 1s²2s²2p⁶3s²3p³. The last electron goes into the p orbital. It is in the 3rd row of the periodic table and the 5th column of the p - block. So, the atomic orbital location is p, row is 3, column is 5, and last electron configuration is 3p3.

Step2: Analyze Tin (Sn)

Tin has an atomic number of 50. Its electron - configuration is [Kr]4d¹⁰5s²5p². The last electron goes into the p orbital. It is in the 5th row and the 2nd column of the p - block. So, atomic orbital location is p, row is 5, column is 2, and last electron configuration is 5p2.

Step3: Consider Copper (Cu)

Copper has an atomic number of 29. Its electron - configuration is [Ar]3d¹⁰4s¹ (due to the stability of the half - filled and fully - filled sub - shells). The last electron goes into the s orbital. It is in the 4th row and the 1st column of the d - block. So, atomic orbital location is d, row is 4, column is 1, and last electron configuration is 4s1.

Step4: Evaluate Technetium (Tc)

Technetium has an atomic number of 43. Its electron - configuration is [Kr]4d⁵5s². The last electron goes into the d orbital. It is in the 5th row and the 5th column of the d - block. So, atomic orbital location is d, row is 5, column is 5, and last electron configuration is 4d5.

Step5: Examine Strontium (Sr)

Strontium has an atomic number of 38. Its electron - configuration is [Kr]5s². The last electron goes into the s orbital. It is in the 5th row and the 2nd column of the s - block. So, atomic orbital location is s, row is 5, column is 2, and last electron configuration is 5s2.

Step6: Look at Neon (Ne)

Neon has an atomic number of 10. Its electron - configuration is 1s²2s²2p⁶. The last electron goes into the p orbital. It is in the 2nd row and the 6th column of the p - block. So, atomic orbital location is p, row is 2, column is 6, and last electron configuration is 2p6.

Step7: Analyze Barium (Ba)

Barium has an atomic number of 56. Its electron - configuration is [Xe]6s². The last electron goes into the s orbital. It is in the 6th row and the 2nd column of the s - block. So, atomic orbital location is s, row is 6, column is 2, and last electron configuration is 6s2.

Step8: Consider Iodine (I)

Iodine has an atomic number of 53. Its electron - configuration is [Kr]4d¹⁰5s²5p⁵. The last electron goes into the p orbital. It is in the 5th row and the 5th column of the p - block. So, atomic orbital location is p, row is 5, column is 5, and last electron configuration is 5p5.

Answer:

Element	Atomic orbital location (s,p,d,f)	Row of element	Column of element in orbital location	Last electron configuration of element (use the boxes from before)
Phosphorus	p	3	5	3p3
Tin	p	5	2	5p2
Copper	d	4	1	4s1
Technetium	d	5	5	4d5
Strontium	s	5	2	5s2
Neon	p	2	6	2p6
Barium	s	6	2	6s2
Iodine	p	5	5	5p5