QUESTION IMAGE
Question
complete the proof that δwyz ≅ δywx.
(image of a quadrilateral wxyz with right angles at x, z and congruence marks on segments and angles)
| statement | reason | |
| 1 | \\(\overline{wz} \perp \overline{yz}\\) | given |
| 2 | \\(\overline{wx} \perp \overline{xy}\\) | given |
| 3 | \\(\angle wyx \cong \angle ywz\\) | given |
| 4 | \\(\angle x \cong \angle z\\) | angles forming a linear pair sum to 180° |
| 5 | \\(\overline{wy} \cong \overline{wy}\\) | reflexive property of congruence |
| 6 | \\(\delta wyz \cong \delta ywx\\) |
Step1: Analyze Given Information
We know \( \overline{WZ} \perp \overline{YZ} \), \( \overline{WX} \perp \overline{XY} \), so \( \angle X = 90^\circ \), \( \angle Z = 90^\circ \), hence \( \angle X \cong \angle Z \) (all right angles are congruent, not the given wrong reason). Also, \( \angle WYX \cong \angle YWZ \) (given), and \( \overline{WY} \cong \overline{WY} \) (reflexive).
Step2: Determine Triangle Congruence Criterion
For triangles \( \triangle WYZ \) and \( \triangle YWX \), we have:
- \( \angle Z \cong \angle X \) (right angles)
- \( \angle YWZ \cong \angle WYX \) (given)
- \( \overline{WY} \cong \overline{WY} \) (common side)
This fits the AAS (Angle - Angle - Side) congruence criterion.
Step3: Correct Reason for Step 4
The reason for \( \angle X \cong \angle Z \) is that all right angles are congruent (since \( \overline{WX} \perp \overline{XY} \) and \( \overline{WZ} \perp \overline{YZ} \) make \( \angle X \) and \( \angle Z \) right angles, so \( \angle X = \angle Z = 90^\circ \)).
Step4: Reason for Step 6
Since we have two angles and a non - included side congruent (AAS), \( \triangle WYZ \cong \triangle YWX \) by AAS Congruence Theorem.
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- For step 4, the correct reason is "All right angles are congruent".
- For step 6, the reason is "AAS (Angle - Angle - Side) Congruence Theorem".