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Question
$\overleftrightarrow{fg} \perp \overleftrightarrow{gh}$ and $\overleftrightarrow{jk} \perp \overleftrightarrow{ij}$. complete the proof that $\angle fgh \cong \angle ijk$.
| statement | reason | |
| 1 | $\overleftrightarrow{fg} \perp \overleftrightarrow{gh}$ | given |
| 2 | $\overleftrightarrow{jk} \perp \overleftrightarrow{ij}$ | given |
| 3 | $m\angle fgh = 90^\circ$ | |
| 4 | $m\angle ijk = 90^\circ$ | |
| 5 | $m\angle fgh = m\angle ijk$ | |
| 6 | $\angle fgh \cong \angle ijk$ | definition of congruence |
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Step1: Reason for Statement 3
If two lines are perpendicular, the angle between them is \(90^\circ\). Since \(\overleftrightarrow{FG} \perp \overleftrightarrow{GH}\), by the definition of perpendicular lines, \(m\angle FGH = 90^\circ\).
Step2: Reason for Statement 4
Similarly, for \(\overleftrightarrow{JK} \perp \overleftrightarrow{IJ}\), using the definition of perpendicular lines, we get \(m\angle IJK = 90^\circ\).
Step3: Reason for Statement 5
Since \(m\angle FGH = 90^\circ\) and \(m\angle IJK = 90^\circ\), by the transitive property of equality (or simply because both equal \(90^\circ\)), \(m\angle FGH = m\angle IJK\).
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- For Statement 3: Definition of perpendicular lines
- For Statement 4: Definition of perpendicular lines
- For Statement 5: Transitive property of equality (or substitution, since both are \(90^\circ\))