Question

complete each row of the table below by filling in the missing prefix or missing exponent.
1 dl = 10 $\square$ l
1 $\square$l = 10 $^{-6}$ l
1 $\square$l = 10 $^{-2}$ l
1 kl = 10 $\square$ l

Explanation:

Step1: Recall metric prefixes

Metric prefixes and their exponents: deci (d) is \(10^{-1}\), micro (\(\mu\)) is \(10^{-6}\), centi (c) is \(10^{-2}\), kilo (k) is \(10^{3}\).

Step2: Solve each row

• For \(1\ \text{dL} = 10^{\square}\ \text{L}\): deci means \(10^{-1}\), so \(\square = -1\).
• For \(1\ \square\text{L} = 10^{-6}\ \text{L}\): \(10^{-6}\) is micro (\(\mu\)), so \(\square = \mu\).
• For \(1\ \square\text{L} = 10^{-2}\ \text{L}\): \(10^{-2}\) is centi (c), so \(\square = \text{c}\).
• For \(1\ \text{kL} = 10^{\square}\ \text{L}\): kilo means \(10^{3}\), so \(\square = 3\).

Answer:

• \(1\ \text{dL} = 10^{-1}\ \text{L}\)
• \(1\ \mu\text{L} = 10^{-6}\ \text{L}\)
• \(1\ \text{cL} = 10^{-2}\ \text{L}\)
• \(1\ \text{kL} = 10^{3}\ \text{L}\)