Question

complete the balanced molecular reaction for the following weak base with a strong acid.
naclo(aq) + h₂so₄(aq) →

Explanation:

Step1: Write the products

When \(NaClO\) (a weak base) reacts with \(H_{2}SO_{4}\) (a strong acid), the products are \(HClO\) (a weak acid) and \(Na_{2}SO_{4}\) (a salt). The un - balanced equation is \(NaClO(aq)+H_{2}SO_{4}(aq)\to HClO(aq)+Na_{2}SO_{4}(aq)\)

Step2: Balance the sodium atoms

On the left - hand side, there is \(1\) \(Na\) atom (\(NaClO\)), and on the right - hand side, there are \(2\) \(Na\) atoms (\(Na_{2}SO_{4}\)). So, we put a coefficient of \(2\) in front of \(NaClO\). The equation becomes \(2NaClO(aq)+H_{2}SO_{4}(aq)\to HClO(aq)+Na_{2}SO_{4}(aq)\)

Step3: Balance the chlorine atoms

After putting a coefficient of \(2\) in front of \(NaClO\), we have \(2\) \(Cl\) atoms on the left. So, we put a coefficient of \(2\) in front of \(HClO\). The equation is \(2NaClO(aq)+H_{2}SO_{4}(aq)\to 2HClO(aq)+Na_{2}SO_{4}(aq)\)

Answer:

\(2NaClO(aq)+H_{2}SO_{4}(aq)\to 2HClO(aq)+Na_{2}SO_{4}(aq)\)