Question

6 colente launches an air rocket in the upward, positive direction. it launches with an initial velocity of 25.5 m/s. it accelerates in the downward, negative direction at a rate of 9.31 m/s². after 3.5 seconds, what is the magnitude of the rockets displacement? 20 meters - 150 meters 150 meters 31 meters

Explanation:

Step1: Identify the kinematic formula

The kinematic formula for displacement is \(x = v_0t+\frac{1}{2}at^{2}\), where \(v_0\) is the initial velocity, \(t\) is the time, and \(a\) is the acceleration.

Step2: Substitute the given values

Given \(v_0 = 25.5\ m/s\), \(t = 3.5\ s\), and \(a=-9.81\ m/s^{2}\) (since acceleration is downward).

$$
LATEXBLOCK0
$$

Answer:

29 meters