QUESTION IMAGE
Question
- classify each function as increasing, decreasing, or constant. explain your reasoning.
a. $f(x) = -\frac{2}{3}x$
b. $f(x) = -2.5$
c. $f(x) = 3x$
Part a: Analyze \( f(x) = -\frac{2}{3}x \)
Step 1: Identify the slope
The function is in the form \( f(x) = mx + b \) (linear function), where \( m = -\frac{2}{3} \) and \( b = 0 \).
Step 2: Determine the trend
For a linear function \( f(x)=mx + b \), if \( m<0 \), as \( x \) increases, \( f(x) \) decreases (since the slope is negative, the line falls from left to right). So \( f(x)=-\frac{2}{3}x \) is a decreasing function.
Part b: Analyze \( f(x) = -2.5 \)
Step 1: Recognize the function type
This is a constant function (it can be written as \( f(x)=0x - 2.5 \)). The value of \( f(x) \) does not change regardless of the value of \( x \).
Step 2: Confirm the trend
For any two values \( x_1 \) and \( x_2 \) (where \( x_1
eq x_2 \)), \( f(x_1)=f(x_2)= - 2.5 \). So the function is constant.
Part c: Analyze \( f(x) = 3x \)
Step 1: Identify the slope
The function is linear with \( m = 3 \) (and \( b = 0 \)).
Step 2: Determine the trend
For a linear function \( f(x)=mx + b \), if \( m>0 \), as \( x \) increases, \( f(x) \) increases (the line rises from left to right). So \( f(x) = 3x \) is an increasing function.
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- a. \( f(x)=-\frac{2}{3}x \) is decreasing (slope \( m = -\frac{2}{3}<0 \), so as \( x \) increases, \( f(x) \) decreases).
- b. \( f(x)= - 2.5 \) is constant (the output value does not change with \( x \)).
- c. \( f(x)=3x \) is increasing (slope \( m = 3>0 \), so as \( x \) increases, \( f(x) \) increases).