QUESTION IMAGE
Question
- the circles have a radius of 1, 2, 3, and 4 units, respectively. the diameter divides each circle into two equal sectors. find the arc length of one half of each of these circles. then fill in the table with the indicated values.
- why does the arc length increase as the radius increases, but the ratio of arc length to the radius remains the same?
Step1: Calculate arc length
The formula for arc length \(s\) is \(s = r\theta\). Since the diameter divides the circle into two equal sectors, the central angle \(\theta=\pi\) radians.
- For \(r = 1\): \(s_1=1\times\pi=\pi\), \(\frac{s_1}{r_1}=\frac{\pi}{1}=\pi\)
- For \(r = 2\): \(s_2=2\times\pi = 2\pi\), \(\frac{s_2}{r_2}=\frac{2\pi}{2}=\pi\)
- For \(r = 3\): \(s_3=3\times\pi=3\pi\), \(\frac{s_3}{r_3}=\frac{3\pi}{3}=\pi\)
- For \(r = 4\): \(s_4=4\times\pi = 4\pi\), \(\frac{s_4}{r_4}=\frac{4\pi}{4}=\pi\)
Step2: Fill in the table
| Radius | Arc Length | \(\frac{\text{Arc Length}}{\text{Radius}}\) | Radian Measure of Central Angle |
|---|---|---|---|
| 2 | \(2\pi\) | \(\pi\) | \(\pi\) |
| 3 | \(3\pi\) | \(\pi\) | \(\pi\) |
| 4 | \(4\pi\) | \(\pi\) | \(\pi\) |
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| Radius | Arc Length | \(\frac{\text{Arc Length}}{\text{Radius}}\) | Radian Measure of Central Angle |
|---|---|---|---|
| 2 | \(2\pi\) | \(\pi\) | \(\pi\) |
| 3 | \(3\pi\) | \(\pi\) | \(\pi\) |
| 4 | \(4\pi\) | \(\pi\) | \(\pi\) |