Question

a circle is centered at ( d(-1,3) ). the point ( g(-10,1) ) is on the circle.
where does the point ( j(-3,12) ) lie?
choose 1 answer:
inside the circle
on the circle
outside the circle

Explanation:

Step1: Calculate the radius of the circle

Use the distance formula \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). For points \(D(-1,3)\) and \(G(-10,1)\), we have \(x_1=-1,y_1 = 3,x_2=-10,y_2 = 1\).

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Step2: Calculate the distance between \(D(-1,3)\) and \(J(-3,12)\)

Let \(x_1=-1,y_1 = 3,x_2=-3,y_2 = 12\) in the distance formula \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)

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Answer:

B. On the circle