Question

choose the solution to this inequality. (\frac{7}{2} geq b + \frac{9}{5})

Explanation:

Step1: Subtract $\frac{9}{5}$ from both sides

To solve for \( b \), we subtract \(\frac{9}{5}\) from both sides of the inequality \(\frac{7}{2} \geq b + \frac{9}{5}\). This gives us \(\frac{7}{2}-\frac{9}{5}\geq b\).

Step2: Find a common denominator

The common denominator of 2 and 5 is 10. So we rewrite the fractions: \(\frac{7\times5}{2\times5}-\frac{9\times2}{5\times2}=\frac{35}{10}-\frac{18}{10}\).

Step3: Subtract the fractions

Subtracting the numerators, we get \(\frac{35 - 18}{10}=\frac{17}{10}\). So the inequality becomes \(b\leq\frac{17}{10}\) (or \(b\leq1.7\)).

Answer:

\(b\leq\frac{17}{10}\) (or \(b\leq1.7\))