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Question
choose the expression that shows the correct product for \\(\sqrt{3} \cdot \sqrt{12}\\).
\\(\sqrt{15}\\)
\\(\sqrt{36}\\)
\\(\sqrt4{15}\\)
\\(\sqrt4{36}\\)
Apply the product rule for radicals
Using the Radical Expressions knowledge point
$$
\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} \quad \text{for } a, b \ge 0
$$
Calculate the product inside the radical
Using the Radical Expressions knowledge point
$$
\sqrt{3} \cdot \sqrt{12} = \sqrt{3 \cdot 12} = \sqrt{36}
$$
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- (A) \(\sqrt{15}\)
- (B) \(\sqrt{36}\) (Correct answer)
- (C) \(\sqrt[4]{15}\)
- (D) \(\sqrt[4]{36}\)