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a chemist prepares a solution of silver oxide (ago) by weighing out 5.1…

Question

a chemist prepares a solution of silver oxide (ago) by weighing out 5.10 mg of silver oxide into a 250. ml volumetric flask and filling the flask to the mark with water.
calculate the concentration in g/dl of the chemists silver oxide solution. be sure your answer has the correct number of significant digits.

Explanation:

Step1: Convert mass from mg to g

We know that \(1\space g = 1000\space mg\). So, for \(m = 5.10\space mg\), we have \(m=\frac{5.10}{1000}\space g=5.10\times10^{- 3}\space g\)

Step2: Convert volume from mL to dL

We know that \(1\space dL=100\space mL\). So, for \(V = 250\space mL\), we have \(V=\frac{250}{100}\space dL = 2.5\space dL\)

Step3: Calculate the concentration

Concentration \(C=\frac{m}{V}\). Substituting \(m = 5.10\times 10^{-3}\space g\) and \(V = 2.5\space dL\) into the formula, we get \(C=\frac{5.10\times 10^{-3}\space g}{2.5\space dL}=2.04\times10^{-3}\space g/dL\)

Answer:

\(2.0\times 10^{-3}\space g/dL\) (rounded to two significant digits as \(5.10\) has three significant digits and \(250\) has two significant digits, and in division, the result is rounded to the least number of significant digits of the values used in the calculation)