Question

a chemist prepares a solution of copper(ii) sulfate (cuso₄) by measuring out 14. g of copper(ii) sulfate into a 300. ml volumetric flask and filling the flask to the mark with water. calculate the concentration in mol/l of the chemists copper(ii) sulfate solution. be sure your answer has the correct number of significant digits. mol/l

Explanation:

Step1: Calculate the molar mass of \(CuSO_4\)

The molar mass of \(Cu\) is \(63.55\space g/mol\), \(S\) is \(32.07\space g/mol\), and \(O\) is \(16.00\space g/mol\).

$$M = 63.55+32.07 + 4\times16.00=159.62\space g/mol$$

Step2: Calculate the number of moles of \(CuSO_4\)

Use the formula \(n=\frac{m}{M}\), where \(m = 14\space g\) and \(M = 159.62\space g/mol\)

$$n=\frac{14}{159.62}\approx0.0877\space mol$$

Step3: Convert the volume of the solution to liters

Given \(V = 300\space mL\), since \(1\space L=1000\space mL\), then \(V = 300\div1000 = 0.300\space L\)

Step4: Calculate the concentration of the solution

Use the formula \(c=\frac{n}{V}\), where \(n = 0.0877\space mol\) and \(V=0.300\space L\)

$$c=\frac{0.0877}{0.300}\approx0.29\space mol/L$$

Answer:

\(0.29\space mol/L\)