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Question
7 chelsea is pulling a box of sporting equipment across a soccer field. she pulls northward with a force of 65.5 n. the force of friction acts southward with a force of 35.2 n. if the box has a mass of 41.8 kg, what is the acceleration of the box once chelsea starts pulling? 0.725 m/s² 1.86 m/s² 1.38 m/s² 1.57 m/s²
Step1: Calculate the net force
The net force \(F_{net}\) is the difference between the pulling force \(F_{pull}\) and the frictional force \(F_{friction}\). Since the forces are in opposite directions (pulling north and friction south), \(F_{net}=F_{pull}-F_{friction}\).
\(F_{pull} = 65.5\space N\), \(F_{friction}=35.2\space N\)
\(F_{net}=65.5 - 35.2=30.3\space N\)
Step2: Use Newton's second law \(F = ma\) to find acceleration \(a\)
Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. We can solve for \(a\) by \(a=\frac{F_{net}}{m}\).
Given \(m = 41.8\space kg\) and \(F_{net}=30.3\space N\)
\(a=\frac{30.3}{41.8}\approx0.725\space m/s^{2}\)
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0.725 m/s²