Question

the charges for four ions are sodium (na) +1, calcium (ca) +2, fluorine (f) -1, and sulfur (s) -2. which would be an ionic bond that could form from any of these ions?
naca₂
na₂s
caf
fs

Explanation:

Step1: Analyze ionic bond formation

Ionic bonds form between oppositely - charged ions. The sum of the charges of the ions in the compound should be zero.

Step2: Check each option

• For \(NaCa_2\): Sodium (\(Na^+\)) and calcium (\(Ca^{2 +}\)) are both cations (positively - charged). Ionic bonds form between cations and anions, so this is not possible.
• For \(Na_2S\): Sodium has a charge of \(+ 1\) (\(Na^+\)) and sulfur has a charge of \(-2\) (\(S^{2-}\)). Using the criss - cross method, if we have \(x\) number of \(Na^+\) and \(y\) number of \(S^{2-}\), then \(x\times(+1)+y\times(-2)=0\). If \(x = 2\) and \(y = 1\), \(2\times(+1)+1\times(-2)=2 - 2=0\).
• For \(CaF\): Calcium has a charge of \(+2\) (\(Ca^{2+}\)) and fluorine has a charge of \(-1\) (\(F^-\)). Using the criss - cross method, if we assume the formula is \(CaF\), then \(1\times(+2)+1\times(-1)=+1

eq0\). The correct formula for calcium and fluorine should be \(CaF_2\) (\(1\times(+2)+2\times(-1)=0\)).

• For \(FS\): Fluorine (\(F^-\)) and sulfur (\(S^{2-}\)) are both anions (negatively - charged). Ionic bonds form between cations and anions, so this is not possible.

Answer:

\(Na_2S\)