Question

a certain rectangle has a perimeter of at least 50. given l represents the length of the rectangle and w represents the width, select the inequality which represents this situation.
17/25
2l + 2w < 50
2l + 2w ≥ 50
2l + 2w > 50
2l + 2w < 50

Explanation:

Step1: Recall the perimeter formula of a rectangle

The perimeter \(P\) of a rectangle is given by \(P = 2L+2W\), where \(L\) is the length and \(W\) is the width.

Step2: Analyze the inequality based on the problem description

The problem states that the perimeter is at least \(50\). The phrase “at least” means “greater than or equal to” in inequality terms. So, if \(P=2L + 2W\) and \(P\geq50\), then \(2L+2W\geq50\).

Answer:

\(2L + 2W\geq50\) (the second option from the top)