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Question
g is the center of the circle.
what will be the next step in constructing the perpendicular bisector of gj?
draw a circle with radius equal to ig and center h.
draw a circle with radius equal to jh and center h.
draw a circle with radius equal to ig and center j.
draw a circle with radius equal to jh and center j.
Step1: Recall the steps of constructing perpendicular bisector
To construct the perpendicular bisector of a line segment \(GJ\), we first have a circle with center \(G\) (radius \(GI\) as \(G\) is the center of the given circle and \(I\) is on the circle). The next step is to draw a circle with the same radius (\(IG\)) but with center \(J\). This is because when we have two circles with the same radius centered at the two endpoints of a line segment (\(G\) and \(J\) here), the intersection points of these two circles will help us draw the perpendicular bisector of the line segment \(GJ\).
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Draw a circle with radius equal to \(IG\) and center \(J\)