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9. a car traveling at 15 m/s starts to decelerate steadily. it comes to…

Question

  1. a car traveling at 15 m/s starts to decelerate steadily. it comes to a complete stop in 10 seconds. what is its acceleration?

Explanation:

Step1: Identify the formula for acceleration

The formula for acceleration is \(a=\frac{v_f - v_i}{t}\), where \(v_f\) is the final velocity, \(v_i\) is the initial velocity, and \(t\) is the time.

Step2: Substitute the given values into the formula

Given \(v_i = 15\ m/s\), \(v_f=0\ m/s\) (since the car comes to a stop), and \(t = 10\ s\).
Substitute into \(a=\frac{v_f - v_i}{t}\): \(a=\frac{0 - 15}{10}\)

Step3: Calculate the acceleration

\(a=\frac{- 15}{10}=-1.5\ m/s^{2}\)

Answer:

The acceleration of the car is \(-1.5\ m/s^{2}\)