Question

a car moving at 25 m/s crashes into a tree and stops in 0.2 s. calculate the force the seat belt exerts on a passenger in the car to bring him to a halt. the mass of the passenger is 63 kg. (enter the magnitude.) \\( \square n \\) resources reading

Explanation:

Step1: Calculate the acceleration

We use the formula \(a=\frac{v - u}{t}\), where \(u = 25\ m/s\), \(v=0\ m/s\), and \(t = 0.2\ s\).

$$a=\frac{0 - 25}{0.2}=\frac{- 25}{0.2}=-125\ m/s^{2}$$

The negative sign indicates deceleration.

Step2: Calculate the force

According to Newton's second law \(F = ma\), with \(m = 63\ kg\) and \(a=- 125\ m/s^{2}\).

$$F=63\times125 = 7875\ N$$

Answer:

\(7875\)