Question

calculate the volume in liters of a 0.010 mol/l zinc nitrate solution that contains 4.00 mol of zinc nitrate (zn(no₃)₂). be sure your answer has the correct number of significant digits.

Explanation:

Step1: Recall molarity formula

The formula for molarity $M=\frac{n}{V}$, where $M$ is molarity, $n$ is the number of moles, and $V$ is the volume in liters. We need to solve for $V$. Rearranging the formula gives $V = \frac{n}{M}$.

Step2: Substitute values

We are given that $n = 4.00\ mol$ and $M=0.010\ mol/L$. Substituting these values into the formula $V=\frac{n}{M}$, we get $V=\frac{4.00\ mol}{0.010\ mol/L}$.

Step3: Calculate volume

$V=\frac{4.00}{0.010}\ L= 400\ L$.

Answer:

$400$