Question

calculate the volume in liters of a 0.00720 mmol/l calcium sulfate solution that contains 150. g of calcium sulfate (caso₄). round your answer to 3 significant digits.

Explanation:

Step1: Calculate the molar mass of \(CaSO_4\)

The molar mass of \(Ca\) is \(40.08\space g/mol\), \(S\) is \(32.07\space g/mol\), and \(O\) is \(16.00\space g/mol\).

$$M = 40.08+32.07 + 4\times16.00=136.15\space g/mol$$

Step2: Calculate the number of moles of \(CaSO_4\)

Using the formula \(n=\frac{m}{M}\), where \(m = 150\space g\) and \(M = 136.15\space g/mol\)

$$n=\frac{150}{136.15}\space mol\approx1.102\space mol$$

Convert moles to millimoles: \(n = 1.102\times10^{3}\space mmol\)

Step3: Use the formula \(V=\frac{n}{C}\) to find the volume

Given \(C=0.00720\space mmol/L\)

$$V=\frac{1.102\times 10^{3}}{0.00720}\space L\approx1.53\times 10^{5}\space L$$

Answer:

\(1.53\times 10^{5}\space L\)