Question

calculate the volume that a 0.323 - mol sample of a gas will occupy at 265 k and a pressure of 0.900 atm.

Explanation:

Step1: <Ideal gas law formula>

$$PV = nRT$$
where \(P = 0.900\ atm\), \(n = 0.323\ mol\), \(T = 265\ K\), and \(R = 0.0821\ L\cdot atm/(mol\cdot K)\)

Step2: <Solve for V>

Rearrange the formula to \(V=\frac{nRT}{P}\)
Substitute the values:
\(V=\frac{0.323\ mol\times0.0821\ L\cdot atm/(mol\cdot K)\times265\ K}{0.900\ atm}\)

Step3: <Calculate the value>

First calculate the numerator: \(0.323\times0.0821\times265 = 0.323\times21.7565=7.0273\)
Then divide by \(0.900\): \(\frac{7.0273}{0.900}\approx7.81\ L\)

Answer:

\(7.81\ L\)