Question

calculate the percentage composition for c₄h₁₀o. (enter your answer to four significant figures.) element % by weight c h o

Explanation:

Step1: Calculate molar mass of \(C_4H_{10}O\)

The molar mass of \(C = 12.01\ g/mol\), \(H= 1.01\ g/mol\), \(O = 16.00\ g/mol\).

$$M = 4\times12.01+10\times1.01 + 16.00=74.14\ g/mol$$

Step2: Calculate percentage of carbon

$$ \%C=\frac{4\times12.01}{74.14}\times 100=\frac{48.04}{74.14}\times100\approx64.79\%$$

Step3: Calculate percentage of hydrogen

$$ \%H=\frac{10\times1.01}{74.14}\times 100=\frac{10.1}{74.14}\times100\approx13.62\%$$

Step4: Calculate percentage of oxygen

$$ \%O=\frac{16.00}{74.14}\times 100\approx21.58\%$$

Answer:

C: 64.79%
H: 13.62%
O: 21.58%