Question

calculate the percent error of a chemical reaction with a theoretical value of -45.68 kj/mol and an experimental value of -54.78 kj/mol.
19.92%
21.37%
20.10%
16.61%

Explanation:

Step1: Calculate the absolute error

The formula for absolute error is \(| \text{Experimental Value}-\text{Theoretical Value}|\).
Here, the experimental value \(E = - 54.78\space kJ/mol\) and the theoretical value \(T=-45.68\space kJ/mol\).
\(|E - T|=|-54.78-(-45.68)|=|-54.78 + 45.68|=| - 9.1|=9.1\)

Step2: Calculate the percent error

The formula for percent error is \(\text{Percent Error}=\frac{|E - T|}{|T|}\times100\%\)
Substitute \(|E - T| = 9.1\) and \(|T| = 45.68\) into the formula.
\(\text{Percent Error}=\frac{9.1}{45.68}\times100\% \)
\(\text{Percent Error}\approx0.1992\times100\%=19.92\%\)

Answer:

19.92%