Question

a. calculate the net force acting on the box in the following problems. 1. 3 n 3 n 2. 4 n 5 n 3. 2 n 4 n 5 n 4. 7 n 4 n 4 n

Explanation:

Step1: Determine direction of forces

For forces acting in the same - direction, we add them; for forces acting in opposite directions, we subtract them.

Step2: Solve problem 1

The two forces are in the same direction. Net force $F_{net1}=3N + 3N=6N$.

Step3: Solve problem 2

The forces are in opposite directions. Net force $F_{net2}=5N - 4N = 1N$ (direction of the 5 - N force).

Step4: Solve problem 3

First, add the forces in the same direction on the left - hand side: $2N+4N = 6N$. Then, find the net force. Since the 6 - N force and the 5 - N force are in opposite directions, $F_{net3}=6N - 5N=1N$ (direction of the 6 - N force).

Step5: Solve problem 4

Add the forces in the same direction on the left - hand side: $7N + 4N=11N$. Add the forces in the same direction on the right - hand side: $4N+4N = 8N$. Then, find the net force. Since the 11 - N force and the 8 - N force are in opposite directions, $F_{net4}=11N - 8N = 3N$ (direction of the 11 - N force).

Answer:

1. $6N$
2. $1N$
3. $1N$
4. $3N$