Question

a bullet is fired from a gun parallel to the ground. at the exact moment it leaves the barrel, a similar bullet is dropped from the same height. which hits the ground first?
neither, they hit at same time
the one from the gun because its moving faster
the dropped one, because its not going as far
youll never find the fired one so it doesnt matter
question 6
10 pts
a ball is dropped on the surface of the earth from a height of 14.49 m. how fast will it be travelling when it hits the ground?

Explanation:

Step1: Use the kinematic equation

The kinematic equation \(v^{2}=v_{0}^{2}+2gh\) is used. Here, the initial velocity \(v_{0} = 0\) (since the ball is dropped), \(g = 9.8\ m/s^{2}\) (acceleration due to gravity), and \(h=14.49\ m\) (height).

Step2: Substitute values into the equation

Substitute \(v_{0} = 0\), \(g = 9.8\ m/s^{2}\), and \(h = 14.49\ m\) into \(v^{2}=v_{0}^{2}+2gh\). We get \(v^{2}=0 + 2\times9.8\times14.49\).
First, calculate \(2\times9.8\times14.49=2\times9.8\times14.49 = 284.004\).
Then, take the square - root of \(v^{2}\). So \(v=\sqrt{284.004}\approx16.85\ m/s\).

Answer:

\(16.85\ m/s\)