Question

1. brad is riding his bicycle on a straight stretch of road. when he passes a traffic light, he begins timing himself. in 29.9 seconds, he cycles 220 meters. his rate of acceleration during this stretch was 0.14 m/s² given this information, what was brads initial velocity when he started timing himself? assume all motion is in the positive direction.

7.9 m/s
2.9 m/s
5.3 m/s
0 m/s

Explanation:

Step1: Use the kinematic equation

The kinematic equation \(s = v_0t+\frac{1}{2}at^{2}\), where \(s = 220\space m\), \(t = 29.9\space s\), \(a=0.14\space m/s^{2}\), and we need to find \(v_0\).

Step2: Rearrange the equation for \(v_0\)

$$
LATEXBLOCK0
$$

Step3: Substitute the values

Substitute \(s = 220\), \(a = 0.14\), \(t = 29.9\) into the formula:

$$
LATEXBLOCK1
$$

Answer:

C. \(5.3\space m/s\)