QUESTION IMAGE
Question
boyles law - color by numbers
directions: answer each question by circling the correct choice. after you have completed all the questions color the picture using the assigned colors. color any unnumbered sections following the pattern.
question 1. the relationship of which two variables is compared in boyles law?
choice a: temperature and pressure (yellow orange)
choice b: volume and temperature (red)
choice c: pressure and volume (light blue)
question 2. which two variables must be held constant for boyles law to apply?
choice a: temperature and moles (yellow green)
choice b: volume and moles (pink)
choice c: pressure and moles (orange)
question 3. which state of matter can be easily compressed?
choice a: solid (purple)
choice b: liquid (blue)
choice c: gas (red)
question 4. according to boyles law, when a gas is held at a constant temperature, as the pressure increases the volume of the gas ______.
choice a: increases (aqua green)
choice b: decreases (pink)
choice c: stays the same (green)
question 5. which of the graphs does not illustrate the relationship described in boyles law?
choice a: graph with p on y - axis and v on x - axis, curve going down (magenta)
choice b: graph with p on y - axis and v on x - axis, curve going up (green)
choice c: graph with p on y - axis and 1/v on x - axis, straight line (blue)
question 6. how does boyles law help explain inhalation?
choice a: when the diaphragm contracts, the volume inside the lungs increases, decreasing the pressure. air rushes in because a gas flows from an area of high pressure to an area of lower pressure. (purple)
choice b: when the diaphragm contracts the volume inside the lungs increases, increasing the pressure. air rushes in because a gas flows from an area of high pressure to an area of lower pressure. (blue)
choice c: when the diaphragm contracts the volume inside the lungs decreases, increasing the pressure. air rushes in because a gas flows from an area of high pressure to an area of lower pressure. (pink)
question 7. if a balloon filled with 850 ml of air at a pressure of 1.5 atmospheres is compressed to half its size before popping, what was the pressure inside the balloon just before popping?
choice a: 3 atm (blue)
choice b: 0.75 atm (red orange)
choice c: 1.5 atm (yellow green)
question 8. if a sample of 1,500 l of nitrogen at an initial pressure of 3.00 atm is compressed until the pressure reaches 50 atm, what will the new volume of this gas be?
choice a: 250 l (sky blue)
choice b: 10 l (purple)
choice c: 90 l (magenta)
question 9. nitrogen is added to bags of chips to prevent staling. a bag of chips containing 220 ml of nitrogen is carried from sea level (1 atm) to denver, where the air pressure is 0.85 atm. what is the new volume of nitrogen in the bag?
choice a: 220 ml (blue)
choice b: 258.82 ml (orange)
choice c: 187 ml (pink)
question 10. if you have 5.6 l of a gas in a piston at a pressure of 3.75 torr and compress the gas until its volume is 4.8 l, what is the new pressure inside the piston?
choice a: 13.95 torr (purple)
choice b: 321.43 torr (red)
choice c: 4.375 torr (aqua green)
question 11. bacteria produce methane gas in sewage - treatment plants. at a sewage - treatment plant in mexico city, bacteria cultures produce 1000 l of methane gas per day at 0.67 atm pressure. what volume tank would be needed to store one days production at 5.0 atm?
choice a: 134 l (yellow orange)
choice b: 742 l (red orange)
choice c: 298 l (light blue)
question 12. a scuba diver uses a tank that delivered 1125 l of a mixture of nitrogen and oxygen at 40 psi. if the original volume of the mixture was 15 l what was the original pressure of the tank?
choice a: 2812 psi (red)
choice b: 1875 psi (magenta)
choice c: 3000 psi (sky blue)
Step1: Recall Boyle's Law
Boyle's Law is $P_1V_1 = P_2V_2$ (constant $T$ and $n$).
Step2: Answer question 1
Boyle's Law compares pressure and volume of a gas. So answer is C. pressure and volume.
Step3: Answer question 2
For Boyle's Law, temperature ($T$) and number of moles ($n$) must be constant. So answer is A. temperature and moles.
Step4: Answer question 3
Gases can be easily compressed. So answer is C. gas.
Step5: Answer question 4
According to Boyle's Law ($P_1V_1=P_2V_2$ at constant $T$ and $n$), when pressure increases, volume decreases. So answer is B. decreases.
Step6: Answer question 5
Boyle's Law is an inverse - relationship ($P\propto\frac{1}{V}$), so the graph that is not a hyper - bola or a straight line for $P$ vs $\frac{1}{V}$ is incorrect. The second graph (a curve that is not a hyper - bola for $P$ vs $V$) is the wrong one. So answer is B.
Step7: Answer question 6
When the diaphragm contracts, lung volume increases, pressure decreases, and air rushes in. So answer is A.
Step8: Answer question 7
Given $V_1 = 850$ ml, $P_1=1.5$ atm, $V_2=\frac{V_1}{2}=425$ ml. Using $P_1V_1 = P_2V_2$, we have $P_2=\frac{P_1V_1}{V_2}=\frac{1.5\times850}{425}=3$ atm. So answer is A. 3 atm.
Step9: Answer question 8
Given $V_1 = 1500$ L, $P_1 = 3.00$ atm, $P_2 = 50$ atm. Using $P_1V_1=P_2V_2$, $V_2=\frac{P_1V_1}{P_2}=\frac{3\times1500}{50}=90$ L. So answer is C. 90 L.
Step10: Answer question 9
Given $V_1 = 220$ ml, $P_1 = 1$ atm, $P_2=0.85$ atm. Using $P_1V_1 = P_2V_2$, $V_2=\frac{P_1V_1}{P_2}=\frac{1\times220}{0.85}\approx258.82$ ml. So answer is B. 258.82 ml.
Step11: Answer question 10
Given $V_1 = 5.6$ L, $P_1 = 3.75$ torr, $V_2 = 4.8$ L. Using $P_1V_1=P_2V_2$, $P_2=\frac{P_1V_1}{V_2}=\frac{3.75\times5.6}{4.8}=4.375$ torr. So answer is C. 4.375 torr.
Step12: Answer question 11
Given $V_1 = 1000$ L, $P_1 = 0.67$ atm, $P_2 = 5.0$ atm. Using $P_1V_1=P_2V_2$, $V_2=\frac{P_1V_1}{P_2}=\frac{0.67\times1000}{5.0}=134$ L. So answer is A. 134 L.
Step13: Answer question 12
Given $V_1 = 15$ L, $V_2 = 1125$ L, $P_2 = 40$ psi. Using $P_1V_1=P_2V_2$, $P_1=\frac{P_2V_2}{V_1}=\frac{40\times1125}{15}=3000$ psi. So answer is C. 3000 psi.
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- C. pressure and volume
- A. temperature and moles
- C. gas
- B. decreases
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- A. 3 atm
- C. 90 L
- B. 258.82 ml
- C. 4.375 torr
- A. 134 L
- C. 3000 psi