Question

1. a boy skips a stone (2.5 grams) across the surface of a pond. he throws the stone with 5 newton of force. what was the stones acceleration?

Explanation:

Step1: Identify the mass and force values

The mass of the stone $m = 2.5\ g=2.5\times10^{- 3}\ kg$ and the force $F = 5\ N$.

Step2: Apply Newton's second - law

Newton's second - law is $F = ma$, where $F$ is the force, $m$ is the mass and $a$ is the acceleration. We can solve for $a$ by the formula $a=\frac{F}{m}$.
Substitute $F = 5\ N$ and $m = 2.5\times10^{-3}\ kg$ into the formula: $a=\frac{5}{2.5\times10^{-3}}$.

Step3: Calculate the acceleration

$a=\frac{5}{2.5\times10^{-3}}=\frac{5\times10^{3}}{2.5}=2000\ m/s^{2}$.

Answer:

$2000\ m/s^{2}$