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a box slides with a velocity of 3.1 m/s across a smooth table before fa…

Question

a box slides with a velocity of 3.1 m/s across a smooth table before falling off. if the box lands 1.9 meters from the table, then how long was the box in the air for? round to 2 decimal places.

Explanation:

Step1: Identify the horizontal - motion formula

In horizontal motion (assuming no air - resistance and smooth table), the horizontal displacement $x$ is given by $x = v_x t$, where $v_x$ is the horizontal velocity and $t$ is the time of flight.
$x = v_x t$

Step2: Solve for the time $t$

We know that $x = 1.9$ m and $v_x=3.1$ m/s. Rearranging the formula $t=\frac{x}{v_x}$.
$t=\frac{1.9}{3.1}$

Step3: Calculate the value of $t$

$t=\frac{1.9}{3.1}\approx0.61$ s

Answer:

$0.61$ s