Question

1. if the box below is 11 kg, what is the acceleration of the box? the force of friction is 50n. 102n

Explanation:

Step1: Calculate the net force

The net force \(F_{net}\) is the applied force \(F_{applied}\) minus the frictional force \(F_{friction}\).
\(F_{net}=F_{applied}-F_{friction}\)
Given \(F_{applied} = 102N\) and \(F_{friction}=50N\), so \(F_{net}=102 - 50=52N\)

Step2: Use Newton's second law \(F = ma\) to find acceleration \(a\)

Newton's second law is \(F_{net}=ma\), where \(m = 11kg\) and \(F_{net}=52N\).
We can solve for \(a\) by the formula \(a=\frac{F_{net}}{m}\)
Substitute \(F_{net} = 52N\) and \(m = 11kg\) into the formula: \(a=\frac{52}{11}\approx4.73m/s^{2}\)

Answer:

The acceleration of the box is approximately \(4.73m/s^{2}\)