Question

a block is pulled by a force of 112 n directed at a \\(39.0^{\circ}\\) angle from the horizontal.

what is the y-component of the force acting on the block?

\\\vec{f}_y = ? \text{ n}\\

Explanation:

⚡ Using what you learned: Vectors in Plane and Space (components, magnitude, direction)

Step 1: Identify given values

$$ F = 112\text{ N} $$

$$ \theta = 39.0^\circ $$

Step 2: Calculate the y-component

$$ F_y = F \sin(\theta) $$

$$ F_y = 112 \cdot \sin(39.0^\circ) $$

$$ F_y \approx 112 \cdot 0.6293 $$

$$ F_y \approx 70.5\text{ N} $$

Answer:

70.5