Question

k bisects \\( \overline { j l } \\). \\( k l = 22 \\) and \\( j l = 2 x \\). find \\( x \\) and \\( j l \\).

Explanation:

Step1: Use the property of a bisector

Since \(K\) bisects \(\overline{JL}\), then \(JK = KL\). Given \(KL = 22\), so \(JK=22\).

Step2: Calculate \(JL\)

By the segment - addition postulate \(JL=JK + KL\). Substituting \(JK = 22\) and \(KL = 22\), we get \(JL=22 + 22=44\).

Step3: Solve for \(x\)

Given \(JL = 2x\) and \(JL = 44\), then \(2x=44\). Dividing both sides by \(2\), we have \(x=\frac{44}{2}=22\).

Answer:

\(x = 22\)
\(JL = 44\)