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√4 = ? betweens 1&2 2&3 3&4 4&5 5&6 6&7 7&8 8&9 9&10 0 1 2 3 4 5 6 7 8 …

Question

√4 = ?
betweens
1&2 2&3 3&4 4&5 5&6 6&7 7&8 8&9 9&10
0 1 2 3 4 5 6 7 8 9 10 11

Explanation:

Step1: Recall square root definition

The square root of a number \( x \), denoted \( \sqrt{x} \), is a value \( y \) such that \( y^2 = x \).

Step2: Calculate \( \sqrt{4} \)

We need to find \( y \) where \( y^2 = 4 \). We know that \( 2^2 = 4 \) (since \( 2\times2 = 4 \)), so \( \sqrt{4}=2 \).

Answer:

\( 2 \)