Question

based on the solubility rules, which of the following will occur if solutions of cuso₄(aq) and bacl₂(aq) are mixed?
cucl₂ will precipitate; ba²⁺ and so₄²⁻ are spectator ions.
cuso₄ will precipitate; ba²⁺ and cl⁻ are spectator ions.
baso₄ will precipitate; cu²⁺ and cl⁻ are spectator ions.
bacl₂ will precipitate; cu²⁺ and so₄²⁻ are spectator ions.
no precipitate will form.

Explanation:

Step1: Write the reaction equation

$CuSO_4(aq)+BaCl_2(aq)
ightarrow CuCl_2(aq) + BaSO_4(s)$

Step2: Apply solubility rules

Chlorides are generally soluble, so $CuCl_2$ is soluble. Sulfates are generally soluble, but $BaSO_4$ is an exception and is insoluble. Spectator ions are those that do not participate in the formation of the precipitate. In this reaction, $Cu^{2 +}$ and $Cl^-$ remain in solution and are spectator ions.

Answer:

$BaSO_4$ will precipitate; $Cu^{2+}$ and $Cl^-$ are spectator ions.