Question

if a balloon is filled with air to a volume of 567. ml at a temperature of 60.°c, then cooled at constant pressure to a temperature of 198. k. what is the final volume (in ml) of the balloon? please report just the numerical answer to three significant figures, do not enter units of ml, and enter your answer using scientific notation.

Explanation:

Step1: Convert initial temperature to Kelvin

$$T_1 = 60. + 273.15 = 333.15\ K$$

Step2: Apply Charles's Law ($\frac{V_1}{T_1}=\frac{V_2}{T_2}$)

$$V_2=\frac{V_1\times T_2}{T_1}$$
Substitute $V_1 = 567\ mL$, $T_1 = 333.15\ K$, and $T_2 = 198\ K$:
$$V_2=\frac{567\times198}{333.15}$$

Step3: Calculate the value

$$V_2=\frac{112266}{333.15}\approx 337$$
In scientific notation: $3.37\times 10^{2}$

Answer:

$3.37\times 10^{2}$