Question

a balloon has 1.00 l gas at sea level (1.00 atm). if the balloon is taken to a point with air pressure of 0.850 atm, what will the new volume be in liters?

• your answer should have three significant figures (round your answer to two decimal places).
• do not include units in your response.

Explanation:

Step1: Apply Boyle's Law

$$P_1V_1 = P_2V_2$$

Step2: Rearrange for \(V_2\)

$$V_2=\frac{P_1V_1}{P_2}$$

Step3: Substitute values

Given \(P_1 = 1.00\), \(V_1 = 1.00\), \(P_2=0.850\)
$$V_2=\frac{1.00\times1.00}{0.850}$$

Step4: Calculate

$$V_2=\frac{1}{0.850}\approx1.18$$

Answer:

1.18