balancing chemical equations
balance the equations below:
1) ____ n₂ + ____ h₂ → ____ nh₃
2) ____ kclo₃ → ____ kcl + ____ o₂
3) ____ nacl + ____ f₂ → ____ naf + ____ cl₂
4) ____ h₂ + ____ o₂ → ____ h₂o
5) ____ pb(oh)₂ + ____ hcl → ____ h₂o + ____ pbcl₂
6) ____ albr₃ + ____ k₂so₄ → ____ kbr + ____ al₂(so₄)₃
7) ____ ch₄ + ____ o₂ → ____ co₂ + ____ h₂o
8) ____ c₃h₈ + ____ o₂ → ____ co₂ + ____ h₂o
9) ____ c₈h₁₈ + ____ o₂ → ____ co₂ + ____ h₂o
10) ____ fecl₃ + ____ naoh → ____ fe(oh)₃ + ____ nacl
11) ____ p + ____ o₂ → ____ p₂o₅

Question

balancing chemical equations
balance the equations below:
1)  ____ n₂ + ____ h₂ → ____ nh₃
2)  ____ kclo₃ → ____ kcl + ____ o₂
3)  ____ nacl + ____ f₂ → ____ naf + ____ cl₂
4)  ____ h₂ + ____ o₂ → ____ h₂o
5)  ____ pb(oh)₂ + ____ hcl → ____ h₂o + ____ pbcl₂
6)  ____ albr₃ + ____ k₂so₄ → ____ kbr + ____ al₂(so₄)₃
7)  ____ ch₄ + ____ o₂ → ____ co₂ + ____ h₂o
8)  ____ c₃h₈ + ____ o₂ → ____ co₂ + ____ h₂o
9)  ____ c₈h₁₈ + ____ o₂ → ____ co₂ + ____ h₂o
10) ____ fecl₃ + ____ naoh → ____ fe(oh)₃ + ____ nacl
11) ____ p + ____ o₂ → ____ p₂o₅

Accepted Answer

# Explanation:
## Step1: Balance nitrogen atoms
For $N_2 + H_2
ightarrow NH_3$, there are 2 N atoms on the left. So we put 2 in front of $NH_3$: $N_2 + H_2
ightarrow 2NH_3$
## Step2: Balance hydrogen atoms
Now there are 6 H atoms on the right. So we put 3 in front of $H_2$: $N_2+3H_2 = 2NH_3$

## Step3: For $KClO_3
ightarrow KCl + O_2$, balance oxygen atoms
The least - common multiple of 3 and 2 (the number of O atoms in $KClO_3$ and $O_2$ respectively) is 6. Put 2 in front of $KClO_3$ and 3 in front of $O_2$: $2KClO_3
ightarrow KCl + 3O_2$
## Step4: Balance K and Cl atoms
Put 2 in front of $KCl$: $2KClO_3=2KCl + 3O_2$

## Step5: For $NaCl+F_2
ightarrow NaF + Cl_2$, balance Cl and F atoms
Put 2 in front of $NaCl$ and $NaF$: $2NaCl+F_2 = 2NaF+Cl_2$

## Step6: For $H_2+O_2
ightarrow H_2O$, balance oxygen atoms
Put 2 in front of $H_2O$: $H_2+O_2
ightarrow 2H_2O$
## Step7: Balance hydrogen atoms
Put 2 in front of $H_2$: $2H_2+O_2 = 2H_2O$

## Step8: For $Pb(OH)_2+HCl
ightarrow H_2O+PbCl_2$, balance Cl atoms
Put 2 in front of $HCl$: $Pb(OH)_2 + 2HCl
ightarrow H_2O+PbCl_2$
## Step9: Balance H and O atoms
Put 2 in front of $H_2O$: $Pb(OH)_2+2HCl = 2H_2O+PbCl_2$

## Step10: For $AlBr_3+K_2SO_4
ightarrow KBr+Al_2(SO_4)_3$, balance Al atoms
Put 2 in front of $AlBr_3$: $2AlBr_3+K_2SO_4
ightarrow KBr+Al_2(SO_4)_3$
## Step11: Balance $SO_4$ groups
Put 3 in front of $K_2SO_4$: $2AlBr_3 + 3K_2SO_4
ightarrow KBr+Al_2(SO_4)_3$
## Step12: Balance Br and K atoms
Put 6 in front of $KBr$: $2AlBr_3+3K_2SO_4 = 6KBr+Al_2(SO_4)_3$

## Step13: For $CH_4+O_2
ightarrow CO_2+H_2O$, balance H atoms
Put 2 in front of $H_2O$: $CH_4+O_2
ightarrow CO_2+2H_2O$
## Step14: Balance O atoms
Put 2 in front of $O_2$: $CH_4+2O_2 = CO_2+2H_2O$

## Step15: For $C_3H_8+O_2
ightarrow CO_2+H_2O$, balance C atoms
Put 3 in front of $CO_2$: $C_3H_8+O_2
ightarrow 3CO_2+H_2O$
## Step16: Balance H atoms
Put 4 in front of $H_2O$: $C_3H_8+O_2
ightarrow 3CO_2 + 4H_2O$
## Step17: Balance O atoms
Put 5 in front of $O_2$: $C_3H_8+5O_2=3CO_2 + 4H_2O$

## Step18: For $C_8H_{18}+O_2
ightarrow CO_2+H_2O$, balance C atoms
Put 8 in front of $CO_2$: $C_8H_{18}+O_2
ightarrow 8CO_2+H_2O$
## Step19: Balance H atoms
Put 9 in front of $H_2O$: $C_8H_{18}+O_2
ightarrow 8CO_2+9H_2O$
## Step20: Balance O atoms
The number of O atoms on the right is $8\times2 + 9\times1=25$. So put $\frac{25}{2}$ in front of $O_2$. Multiply all coefficients by 2: $2C_8H_{18}+25O_2 = 16CO_2+18H_2O$

## Step21: For $FeCl_3+NaOH
ightarrow Fe(OH)_3+NaCl$, balance Cl atoms
Put 3 in front of $NaCl$: $FeCl_3+NaOH
ightarrow Fe(OH)_3+3NaCl$
## Step22: Balance Na and O atoms
Put 3 in front of $NaOH$: $FeCl_3+3NaOH = Fe(OH)_3+3NaCl$

## Step23: For $P + O_2
ightarrow P_2O_5$, balance P atoms
Put 2 in front of $P$: $2P+O_2
ightarrow P_2O_5$
## Step24: Balance O atoms
Put $\frac{5}{2}$ in front of $O_2$. Multiply all coefficients by 2: $4P + 5O_2=2P_2O_5$

# Answer:
1. $1N_2+3H_2 = 2NH_3$
2. $2KClO_3=2KCl + 3O_2$
3. $2NaCl+F_2 = 2NaF+Cl_2$
4. $2H_2+O_2 = 2H_2O$
5. $Pb(OH)_2+2HCl = 2H_2O+PbCl_2$
6. $2AlBr_3+3K_2SO_4 = 6KBr+Al_2(SO_4)_3$
7. $CH_4+2O_2 = CO_2+2H_2O$
8. $C_3H_8+5O_2=3CO_2 + 4H_2O$
9. $2C_8H_{18}+25O_2 = 16CO_2+18H_2O$
10. $FeCl_3+3NaOH = Fe(OH)_3+3NaCl$
11. $4P + 5O_2=2P_2O_5$

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QUESTION IMAGE

Question

Explanation:

Step1: Balance nitrogen atoms

Step2: Balance hydrogen atoms

Step3: For \(KClO_3

Step4: Balance K and Cl atoms

Step5: For \(NaCl+F_2

Step6: For \(H_2+O_2

Step7: Balance hydrogen atoms

Step8: For \(Pb(OH)_2+HCl

Step9: Balance H and O atoms

Step10: For \(AlBr_3+K_2SO_4

Step11: Balance \(SO_4\) groups

Step12: Balance Br and K atoms

Step13: For \(CH_4+O_2

Step14: Balance O atoms

Step15: For \(C_3H_8+O_2

Step16: Balance H atoms

Step17: Balance O atoms

Step18: For \(C_8H_{18}+O_2

Step19: Balance H atoms

Step20: Balance O atoms

Step21: For \(FeCl_3+NaOH

Step22: Balance Na and O atoms

Step23: For \(P + O_2

Step24: Balance O atoms

Answer: