Question

the balanced chemical equation for the reaction of ammonia (nh₃) when it reacts with copper(ii)oxide (cuo) to give diatomic nitrogen, copper element and water as the products, is 2nh₃(g) + 3cuo(s) → n₂(g) + 3cu(s)+ 3h₂o(l). suppose you took 18.1g of nh₃ for an experiment, then, how many mols of nh₃ do you have? n = 14.01amu; h=1.008amu).

1. 1.06mols
2. 14.01mols
3. 18.1mols
4. 20.2 mols

Explanation:

Step1: Calculate molar mass of \(NH_3\)

Molar mass of \(NH_3\) = mass of N + 3×mass of H.
\(= 14.01 + 3\times1.008\)
\(= 14.01 + 3.024 = 17.034\space g/mol\).

Step2: Use moles formula (\(n = \frac{m}{M}\))

Given mass (\(m\)) = 18.1 g, molar mass (\(M\)) = 17.034 g/mol.
\(n = \frac{18.1}{17.034} \approx 1.06\space mols\).

Answer:

1. 1.06mols