Question

balance the reaction, do not leave any fractions, dont leave anything blank, then answer the questions about the reaction
1 c₉h₁₈ + 2 o₂ → 3 co₂(g) + 4 h₂o
this is an 5 reaction.
is this a redox reaction? (yes/no)6, because o₂⁰ is reduced to o⁻², and because c⁻⁴ is 7 to c⁺⁴.
will the reaction happen as it is written? (yes/no)8, because this is known to be an exothermic reaction and because co₂ and h₂o are 9. the reverse reaction would not happen.
a. 1 b. 2 c. 3 d. 4 e. 5 f. 6 g. 7 h. 8
i. 9 j. 10 k. 12 l. 14 m. 16 n. 18 o. 20 p. 21
q. 24 r. 26 s. 27 t. synthesis u. decomposition
v. single displacement w. double displacement x. neutralization
y. combustion z. yes aa. no bb. reactive cc. stable
dd. oxidized ee. reduced

Explanation:

Step1: Balance carbon atoms

For \(C_9H_{18}\), there are 9 carbon atoms. So, the coefficient of \(CO_2\) (\(3\)) is 9.

Step2: Balance hydrogen atoms

There are 18 hydrogen atoms in \(C_9H_{18}\). So, the coefficient of \(H_2O\) (\(4\)) is 9.

Step3: Balance oxygen atoms

The right - hand side has \(9\times2 + 9\times1=27\) oxygen atoms. So, the coefficient of \(O_2\) (\(2\)) is \(\frac{27}{2}\). But we need to multiply all coefficients by 2 to get rid of the fraction. So, the balanced equation is \(2C_9H_{18}+27O_2
ightarrow18CO_2 + 18H_2O\).

This is a combustion reaction (\(5 = Y\)).

Since \(O\) is reduced (\(O_2^0
ightarrow O^{- 2}\)) and \(C\) is oxidized (\(C^{-4}
ightarrow C^{+4}\)), it is a redox reaction (\(6 = Z\), \(7 = DD\)).

Combustion reactions are exothermic and produce stable products (\(CO_2\) and \(H_2O\) are stable, \(9 = CC\)). So, the reaction will happen as written (\(8 = Z\)).

Answer:

1. \(2\)
2. \(27\)
3. \(18\)
4. \(18\)
5. \(Y\)
6. \(Z\)
7. \(DD\)
8. \(Z\)
9. \(CC\)