Question

balance the chemical equation using the smallest possible whole number coefficients.
if the coefficient is 1, you may leave it blank.

b (s) + h₂ (g) → b₂h₆ (g)
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Explanation:

Step1: Balance B atoms

On the right - hand side, there are 2 B atoms in \(B_2H_6\). So, we put a coefficient of 2 in front of B on the left - hand side: \(2B(s)+\square H_2(g)\to\square B_2H_6(g)\)

Step2: Balance H atoms

On the right - hand side, there are 6 H atoms in \(B_2H_6\). Since each \(H_2\) molecule has 2 H atoms, we put a coefficient of 3 in front of \(H_2\): \(2B(s)+3H_2(g)\to1B_2H_6(g)\)

Answer:

2, 3, 1