Question

assignment
find the value of each trigonometric ratio. soh cah toa sine=opposite/hypotenuse
cosine = adjacent/hypotenuse tangent = opposite /adjacent (lets do 1 - 12 together, then
13 - 20 are due for a grade)

1. sin a
2. sin z
3. sin z
4. sin c
5. cos c
6. cos z
7. cos x
8. cos z
9. tan x
10. tan z

Explanation:

Step1: Recall SOH formula

$\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$

Step2: Identify sides for $\sin A$

For angle $A$ in $\triangle ABC$, opposite side to $A$ is $BC = 20$, hypotenuse is $AC=25$
$\sin A=\frac{BC}{AC}$

Step3: Calculate the ratio

$\sin A=\frac{20}{25}=\frac{4}{5}$

Answer:

$\frac{4}{5}$