Question

is the area, in square meters, of the isosceles trapezoid below? 18.6 m 7.2 m 9.2 m

Explanation:

Step1: Recall the trapezoid area formula

The area formula for a trapezoid is \(A=\frac{(b_1 + b_2)h}{2}\), where \(b_1\) and \(b_2\) are the lengths of the two parallel sides (bases), and \(h\) is the height.

Step2: Identify the values of \(b_1\), \(b_2\), and \(h\)

From the problem, \(b_1 = 18.6\space m\), \(b_2=9.2\space m\), and \(h = 7.2\space m\).

Step3: Substitute the values into the formula

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Step4: Calculate the result

\(27.8\times3.6=(27 + 0.8)\times3.6=27\times3.6+0.8\times3.6=(20\times3.6+7\times3.6)+2.88=(72 + 25.2)+2.88 = 97.2+2.88=100.08\)

Answer:

\(100.08\space m^{2}\)