QUESTION IMAGE
Question
area? (2.5 points)
here is a right square pyramid. round answers in this problem to the neares
if necessary.
what is the height of the pyramid? (1 point)
what is the volume of the pyramid? (1 point)
Height of the Pyramid
Step1: Identify the right triangle
The base of the square pyramid is a square with side length 6, so the distance from the center of the base to the midpoint of a base edge is half of 6, which is 3. The slant edge (from the apex to the midpoint of a base edge) is 5. We can use the Pythagorean theorem \( a^2 + b^2 = c^2 \) where \( c = 5 \) (the slant edge), \( b = 3 \) (half of the base side), and \( a \) is the height \( h \) of the pyramid.
Step2: Apply the Pythagorean theorem
We have \( h^2 + 3^2 = 5^2 \). So \( h^2 = 5^2 - 3^2 = 25 - 9 = 16 \). Then \( h=\sqrt{16} = 4 \).
Step1: Recall the volume formula for a pyramid
The volume \( V \) of a pyramid is given by \( V=\frac{1}{3}Bh \), where \( B \) is the area of the base and \( h \) is the height.
Step2: Calculate the base area
The base is a square with side length 6, so the area of the base \( B = 6\times6=36 \).
Step3: Substitute values into the volume formula
We know the height \( h = 4 \) from the previous calculation. So \( V=\frac{1}{3}\times36\times4 \).
Step4: Compute the volume
\( \frac{1}{3}\times36 = 12 \), and \( 12\times4 = 48 \).
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The height of the pyramid is 4.