Question

area of nets
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#3
#1
115
cm²
#11
#2
408
ft²
#12
#3
cm²
#13
#4
#5
#6
#7
#8
#9
#10
#14
#15
#16
#17
#18
120
cm²
#19
#20
e triangular pyramid to
e surface area.
6 cm
6 cm
3 cm

Explanation:

Step1: Calculate the area of one triangular face

The formula for the area of a triangle is \(A = \frac{1}{2}bh\). Here, \(b = 6\space cm\) and \(h=6\space cm\). So, \(A_1=\frac{1}{2}\times6\times6 = 18\space cm^{2}\)

Step2: Calculate the area of another triangular face

For the triangle with \(b = 6\space cm\) and \(h = 6\space cm\), we already found its area as \(18\space cm^{2}\) (same as step 1 since they have the same base and height)

Step3: Calculate the area of the third triangular face

For the triangle with \(b = 6\space cm\) and \(h = 6\space cm\), \(A_3=\frac{1}{2}\times6\times6=18\space cm^{2}\)

Step4: Calculate the area of the fourth triangular face

For the triangle with \(b = 6\space cm\) and \(h = 3\space cm\), \(A_4=\frac{1}{2}\times6\times3 = 9\space cm^{2}\)

Step5: Sum up all the areas

The surface area \(S=A_1 + A_2+A_3 + A_4=18 + 18+18 + 9=63\space cm^{2}\)

Answer:

\(63\)