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solve for a. figures are not necessarily drawn to scale.
question 2
Step1: Determine similar triangles
Since \(\angle T = \angle T\) (common angle) and \(\angle TVU=\angle TSR = 30^{\circ}\), \(\triangle TVU\sim\triangle TSR\) (by AA - Angle - Angle similarity criterion).
Step2: Use the property of similar triangles
For similar triangles, the ratios of corresponding sides are equal. That is \(\frac{TV}{TS}=\frac{TU}{TR}\).
We know that \(TV = 8\), \(TS=8 + 6=14\), \(TU = 4\) and \(TR=x\).
Substituting the values into the proportion \(\frac{8}{14}=\frac{4}{x}\).
Step3: Cross - multiply to solve for \(x\)
Cross - multiplying gives us \(8x=14\times4\).
So \(8x = 56\).
Dividing both sides by 8: \(x=\frac{56}{8}\).
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\(x = 7\)